2x^2+3xy+2y^2=4

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Solution for 2x^2+3xy+2y^2=4 equation: 


Simplifying
2x2 + 3xy + 2y2 = 4

Reorder the terms:
3xy + 2x2 + 2y2 = 4

Solving
3xy + 2x2 + 2y2 = 4

Solving for variable 'x'.

Reorder the terms:
-4 + 3xy + 2x2 + 2y2 = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 3xy + 2x2 + 2y2 = 0

The solution to this equation could not be determined.

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